# How to estimate the cost of tile flooring

This construction article briefly explains the process required for working out the cost of entire tile flooring.

Here, measuring unit is taken as square metre.

Detail tile flooring process :-

a. Initially, it is necessary to fill the flooring area having cement mortar (1:4 ratio) at a least thickness (50 mm). The thickness of the cement sand mortar may be raised to amend the height of the floor.

b. After that, the tiles should be placed on the cement, sand mortar.

Suppose, the cost of tile is calculated based on the following room :-

The calculation of tile is done based on the following dimension :-

From the figure,

Size of the room = 4 m × 3 m

Size of the tile = 0.3 m × 0.3 m

Assume that total 133 numbers of tiles are necessary for this room. (the skirting tiles area is exempted here).

Mortar for tile flooring is calculated as follow :-

From the Figure,

Wet Volume of the cement mortar necessary = Area of the room × Cement Mortar Thickness

= 12 m^{2} × 0.05 m

Wet Volume of the cement mortar necessary = 0.6 m^{3}

1.5 m^{3} volume of wet cement mortar is required here i.e. more volume is necessary once the water is added to cement and sand mix.

Dry volume of mortar is taken as 25% of more of wet volume.

The dry volume is computed as follow:-

Dry Volume of cement mortar = 0.6 m^{3} X (1+0.25)

= 0.6 m^{3} X 1.25

Dry Volume of cement mortar = 0.75 m^{3}

Cement and Sand Calculation

Workout cement and sand for tile flooring, (1:4 ratio)

1 Cement : 4 Sand = Dry Volume of Cement Mortar

1 part of cement : 4 part of sand = 0.75 m^{3} (Total 5 parts)

So, Cement = 0.75 m^{3} /5

= 0.15 m^{3}

It is known 1 bag of cement = 0.035 m^{3}

Necessary Cement Bags = 0.15 / 0.035

= 4.29 Bags

Necessary Cement Bags = 4.3 Bags (Approx)

Therefore, Required Sand = (0.75 m^{3} / 5) X 4

Required Sand = 0.6 m^{3}

So, it is found that 4.3 Cement Bags, 0.6 m^{3} Sand and 133 number of tiles are essential for the room.